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Ring structure of glucose is due to form...

Ring structure of glucose is due to formation of hemiacetal and ring formation between:

A

`C_(1)` and `C_(5)`

B

`C_(1)` and `C_(4)`

C

`C_(1)` and `C_(3)`

D

`C_(2)` and `C_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
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Knowledge Check

  • The predominant ring structure of glucose in aqueous solution is called

    A
    cyclopentyl
    B
    furanose
    C
    pyranose
    D
    none of the above

  • The brown ring test for NO_(3)^(-) is due to the formation of the complex ion with formula:

    A
    `[Fe(H_(2)O)_(6)]^(2+)`
    B
    `Fe[NO(CN)_(5)]^(2-)`
    C
    `[Fe(H_(2)O_(5)NO]^(2+)`
    D
    `[Fe(H_(2O)(NO)_(5)]^(2+)`

  • Treatment of glucose with nitric acid leads to the formation of a

    A
    monocarboxylic acid
    B
    dicarboxylic acid
    C
    tricarboxylic acid
    D
    tetracarboxylic acid

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    In the ring structure of fructose, the anomeric carbon is

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    Which of the statements given below is not true about formation of annual rings in trees?

    Statement-I: per molecule of Glucose consumes two molecule of Ph-NH-NH_(2) during formation of osazone. Statement-II: Structure of Glucose osazone is:

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