Home
Class 12
CHEMISTRY
IfN(1),N(2),N(3),……are the number of mol...

If`N_(1),N_(2),N_(3),……`are the number of molcules with molecular masses `M_(1),M_(2),M_(3),…`respectively ,then mass average molar mass is expressed as:

A

`(SigmaN_(i)M_(i)^(2))/(SigmaN_(i)M_(i))`

B

`(SigmaN_(i)M_(i))/(SigmaN_(i))`

C

`(SigmaM_(i)^(2)/(SigmaN_(i)`

D

`(SigmaN_(i)M_(i))/(SigmaM_(i)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • POLYMERS

    HIMANSHU PANDEY|Exercise Only One Correct Answer (Q.26 To Q.50)|25 Videos

  • POLYMERS

    HIMANSHU PANDEY|Exercise Only One Correct Answer (Q.51 To Q.75)|25 Videos

  • NOMENCLATURE

    HIMANSHU PANDEY|Exercise Section Iv (Q.26 To Q.26)|1 Videos

  • PRACTICAL ORGANIC CHEMISTRY

    HIMANSHU PANDEY|Exercise Match The Column|6 Videos

Similar Questions

Explore conceptually related problems

If N_(1), N_(2), N_(3) ………Are the number of molecules with molecular masses M_(1), M_(2), M_(3) …….respectively, then average molecular mass is expressed as

Three perfect gases at absolute temperature T_(1), T_(2) and T_(3) are mixed. The masses f molecules are m_(1), m_(2) and m_(3) and the number of molecules are n_(1), n_(2) and n_(3) respectively. Assuming no loss of energy, the final temperature of the mixture is

Three containes of the same volume contain three different gases. The masses of the molecules are m_(1), m_(2) and m_(3) and the number of molecules in their respective containers are N_(1), N_(2) and N_(3) . The gas pressure in the containers are P_(1), P_(2) and P_(3) respectively. All the gases are now mixed and put in one of the containers. The pressure P of mixture will be

The oxide of an element possess the molecular formula M_(2)O_(3) . If the equivalent mass of the metal is 9, the molecular mass of the oxide will be

Two ideal polyatomic gases at temperature T_(1) and T_(2) are mixed so that there is no loss of energy . If F_(1) and F_(2), m_(1) and m_(2) ,n_(1) and n_(2) be the degrees of freedom, masses, number of molecules of the firest and second gas respectively, the temperature of mixture of these two gases is :

Relation belween number of average molecular mass (overline(M)_(n)) and weight of average molecular mass (overline(M)_(w)) of synthetid polymers is

Two perfect gases at absolute temperature T_(1) and T_(2) are mixed. There is no loss of energy. The masses of the molecules are m_(1) and m_(2) . The number of molecules in the gases are n_(1) and n_(2) . The temperature of the mixture is

Equal volumes of two different gases 1 and 2 with respective molecular masses M_(1) and M_(2) are the same temperature (T) and pressure (P) , if M_(1) gt M_(2) , then which of the following is true regarding the number of molecules (N) ?

For the reaction, N_(2)(g)+3H_(2)(g)to 2NH_(3)(g) , if molecular masses of NH_(3) " and " N_(2) " and " M_(1) " and" M_(2) , their equivalent masses are E_(1) " and" E_(2) , then (E_(1)-E_(2)) is :