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SUBHASH PUBLICATION-MATHEMATICAL INDUCTION-FIVE MARKS QUESTIONS WITH ANSWERS
- 1+2+3+............+n=(n(n+1))/2 forall n in N.
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- 1^(2)+2^(2)+3^(2)+............+n^(2)=(n(n+1)(2n+1))/6 forall n in N.
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- 1^(3)+2^(3)+3^(3)+………….+n^(3)=(n^(2)(n+1)^(2))/4 forall n in N.
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- 1.2+2.3+3.4+…………..+n(n+1)=n/3(n+1)(n+2) forall n in N.
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- 1/1.2+1/2.3+1/3.4+…………….+1/(n(n+1))=n/(n+1) forall n in N.
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- 1*2*3+2*3*4+...+n(n+1)(n+2)=(n(n+1)(n+2)(n+3))/4 forall n in N.
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- Prove that by using the principle of mathematical induction for all n...
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- 1/(2*5)+1/(5*8)+1/(8*11)+............1/((3n-1)(3n+2))=n/((6n+4)) foral...
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- a+ar+ar^(2)+...+ar^(n-1)=(a(1-r^(n)))/(1-r) forall n in N.
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- (1+3/1)(1+5/4)(1+7/9)...(1+((2n+1))/n^(2))=(n+1)^(2) forall n in N.
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- 1/1.4+1/4.7+1/7.10+...+1/((3n-2)(3n+1))=n/((3n+1)) forall n in N.
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- Prove by induction that : 2^(n) gt n for all n in N.
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- Prove by induction that n(n+1) (2n+1) is divisible by 6.
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- n(n+1)(n+5) is a multiple 3.
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- 10^(2n-1)+1 is divisible by 11.
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- 3^(2n+2)-8n-9 is divisible by 8.
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- 41^(n)-14^(n) is multiple of 27.
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