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The sum of first three terms of a G.P is...

The sum of first three terms of a G.P is `(39)/(10)` and their product is 1. Find the common ratio and the terms.

Text Solution

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Let terms be `(a)/(r)` a,ar
Given `(a)/(r)."a.ar"=1rArra^(3)=1rArra=1`
Also `(a)/(r)+a+"ar"=(39)/(10)rArr(1)/(r)+1+r=(39)/(10)`
`rArr10+10r+10r^(2)=39r`
`rArr10r^(2)-29r+10=0`
`rArr(2r-5)(5r-2)=0rArrr=(5)/(2)or(2)/(5)`
When `a=1,r=(2)/(5),(a)/(r)a,"ar"=(5)/(2),1,(2)/(5)`
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