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cot x cot 2x-cot 2x cot3x-cot3x cotx=1...

`cot x cot 2x-cot 2x cot3x-cot3x cotx=1`

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The correct Answer is:
` therefore cot x .cot 2x -cot 2x .cot 3x -cot3x .cot x =1 `
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