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Derive the equation of the ellipse in th...

Derive the equation of the ellipse in the form `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`.

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Define ellipse and derive its equation in the form (x^(2))/(a^(2))+(y^(2))/(b^(2)) = 1(a gt b) .

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If e is the eccentricity of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 , (altb) then

Find the equation of hyperbola in the form (x^2)/(a^2)-(y^2)/(b^2)=1 , given that length of transverse axis = 10 and eccentricity = 2.

The locus of the middle point of the portion of a tangent to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 included between the axes is the curve