Write the value of `cos^2(1/2cos^(-1)3/5)`

Explanation

`cos 2 theta = 2cos^2 theta- 1`

`=> cos^2 theta = (1 + cos 2 theta)/2`

`cos^2 (1/2 cos^-1(3/5))`

`= (1 + cos(2 xx 1/2 cos^-1 (3/5)))/2`

`=> (1 + cos(cos^-1(3/5)))/2`

`= (1 + (3/5))/2 = 8/(2 xx 5)`

`= 4/5`

Answer