`3x - (y+7)/11+2 =10` and `2y+ (x+11)/7 =10`

If A = (3,-4) , B= (7,0) and C = (14 , -7) are the three consecutive vertices of a parallelogram ABCD , then find the slope of the diagonal BD . The following are the steps involved in solving the above problem . Arrange them is sequential order (A) ((x + 7)/(2) , (y + 0)/(2)) = ((3 + 14)/(2) , (-4-7)/(2)) . (B) The slope of BD = (-11-0)/(10-7) = (-11)/(3) . (C) (x+7)/(2) = (17)/(2) and (y+0)/(2) - (-11)/(2) implies x = 10 , y = -11 therefore D = (10 , -11) . (D) Let the fourth vertex be D(x , y) . we know that the diagonals of a parallelogram bisect each other .

Determine the vertices of a triangle, equations of whose sides are given by 3y + x = 5 , 2y - x = 11 and 3y + 2x = 7 .

2x + y = (7xy) / (3), x + 3y = (11xy) / (3)

Solve x + y = 7 and 3x - 2y = 11.

Solve x + y = 7 and 3x - 2y = 11.

Find three different solutions of the each of the following equations. (i) 3x + 4y = 7 (ii) y = 6x (iii) 2x - y = 7 (iv) 13x - 12y = 25 (v) 10x + 11y = 21 (vi) x + y = 0

Find three different solutions of the each of the following equations. (i) 3x + 4y = 7 (ii) y = 6x (iii) 2x - y = 7 (iv) 13x - 12y = 25 (v) 10x + 11y = 21 (vi) x + y = 0

Find three different solutions of the each of the following equations. (i) 3x + 4y = 7 (ii) y = 6x (iii) 2x - y = 7 (iv) 13x - 12y = 25 (v) 10x + 11y = 21 (vi) x + y = 0

Find three different solutions of the each of the following equations. (i) 3x + 4y = 7 (ii) y = 6x (iii) 2x - y = 7 (iv) 13x - 12y = 25 (v) 10x + 11y = 21 (vi) x + y = 0