The distance of the point `theta` on the ellipse `x^2/a^2+y^2/b^2=`1 from a focus is

The distance of the point theta^(prime) on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 from a focus is

The distance of a point on the ellipse x^2/6 + y^2/2 = 1 from the centre is 2. Find the eccentric angle of the point.

The distance of a point on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 from the centre is 2 Then the eccentric angle of the point is

The distance of a point on the ellipse x^(2)//6+y^(2)//2=1 from the centre is 2. The eccentric angle of the point is

The distance of a point on the ellipse (x^2)/6+(y^2)/2=1 from the center is 2. Then the eccentric angle of the point is

The length of the subtangent (if exists) at any point theta on the ellipse x^2/a^2+y^2/b^2=1 is

Show that the maximum distance of centre of the ellipse x^(2)/a^(2)+y^(2)/b^(2) = 1 from a normal to the ellipse is (a - b).

Find the focal distance of point P(theta) on the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1

If the distance of a point on the ellipse (x^(2))/(6) + (y^(2))/(2) = 1 from the centre is 2, then the eccentric angle of the point, is

If the distance of a point of the ellipse x^2/6+y^2/2=1 from the center is 2, then the eccentric angle is