If PSQ is focal chord of parabola `y^2 = 4ax (a gt 0)`, where S is focus then prove that `1/(PS)+1/(SQ) =1/a`

If PSQ is a focal chord of a parabola y^(2)=6x , where S is the focus.Then the minimum value of PS.QS is

If P and Q are the end points of a focal chord of the parabola y^(2)=4ax- far with focus isthen prove that (1)/(|FP|)+(1)/(|FQ|)=(2)/(l), where l is the length of semi-latus rectum of the parabola.

PSQ is a focal chord of the parabola y^2=8x. If\ S P=6, then write SQ.

PSQ is a focal chord of the parabola y^(2)=8xIf SP=6, then write SQ.

For a focal chord PQ of the parabola y^(2)=4ax if SP =l and SQ=l then prove that (1)/(l)+(1)/(l)+(1)/(a).