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If sin^(-1)(1/3)+cos^(-1)x=pi/2,then fin...

If `sin^(-1)(1/3)+cos^(-1)x=pi/2`,then find `x`

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`sin^(−1)(1/3)​+cos^(−1)x=π/2​`
`⇒cos^(−1)x=π/2​−sin^(−1)(1/3)​`
`⇒x=cos(π/2​−sin^(−1)(1/3)​)`
`⇒x=sin(sin^(−1)(1/3)​)`
`∴x=1/3`​
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