Write the value of `2sin^(-1)\ 1/2+cos^(-1)((a-b)/(a+b))`

Explanation

Given,

`2sin^(-1)\ 1/2+cos^(-1)((a-b)/(a+b))`

=`2 xx (pi/6)+cos^(-1)((a-b)/(a+b))`

=`pi/3+cos^(-1)((a-b)/(a+b))`

let `a=cos^2theta ` and `b=sin^2theta`

=`pi/3+cos^(-1)((cos^2theta-sin^2theta)/(cos^2theta+sin^2theta))`

=`pi/3+cos^(-1)(cos2theta)`

=`pi/3+2theta`

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