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Evaluate: sin^(-1)(s in(3pi)/5)...

Evaluate: `sin^(-1)(s in(3pi)/5)`

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To evaluate the expression \( \sin^{-1}(\sin(3\pi/5)) \), we can follow these steps: ### Step 1: Understand the range of the sine inverse function The function \( \sin^{-1}(x) \) (also known as arcsine) has a range of \( \left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \). This means that the output of \( \sin^{-1}(x) \) will always fall within this interval. ### Step 2: Simplify \( \sin(3\pi/5) \) We know that \( 3\pi/5 \) is in the second quadrant. In the second quadrant, the sine function is positive. We can use the identity: \[ ...
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RD SHARMA-INVERSE TRIGONOMETRIC FUNCTION-Solved Examples And Exercises
  1. If sin^(-1)(1/3)+cos^(-1)x=pi/2,then find x

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  2. Write the value of 2sin^(-1)\ 1/2+cos^(-1)((a-b)/(a+b))

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  3. Evaluate: sin^(-1)(s in(3pi)/5)

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  4. If (tan^(-1)x)^(2)+(cot^(-1)x)^(2)=(5 pi^(2))/(8), then the value of x...

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  5. Prove that tan(cot^(-1)x)=cot(tan^(-1)x)

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  6. Evaluate: (i) tan{cos^(-1)(-7/(25))} (ii) "c o s e c"{cot^(-1)(-(12)/...

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  7. Evaluate: sin{cos^(-1)(-(3)/5)+cot^(-1)(-5/(12))}

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  8. If -1lt=x , ylt=1 such that sin^(-1)x+sin^(-1)y=(2pi)/3, find the valu...

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  9. If tan^(-1)x+tan^(-1)y=(4pi)/5, find cot^(-1)x+cot^(-1)ydot

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  10. If tan^(-1)x-cot^(-1)x=tan^(-1)""1/(sqrt(3)) find the value of xdot

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  11. If sin(cos^(-1)(5/13)+sin^(-1)x)=1 find the value of xdot

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  12. If cos(sin^(-1)(2/5)+cos^(-1)x)=0 find the value of xdot

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  13. Evaluate : cos(2cos^(-1)x+sin^(-1)x)a tx=1/5

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  14. Let f(x)=e^(cos^(-1){sin(x+pi/3)}) Then, f((8pi)/9)= (a)e^(5pi//18...

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  15. If u=cot^(-1)sqrt(tanalpha)-tan^(-1)sqrt(tanalpha),t h e ntan(pi/4- u/...

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  16. The number of real solutions of the equation sqrt(1+cos2x)=sqrt(2)sin^...

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  17. If alpha=tan^(-1)(t a n(5pi)/4)a n dbeta=tan^(-1)(-tan(2pi)/3),t h e n...

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  18. The domain of cos^(-1)(x^2-4) is (a) [3,5] (b) [-1,1] (c)[-sqrt(5),-...

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  19. In a A B C , , if C is a right angle, then tan^(-1)(a/(b+c))+tan^(-1...

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  20. If 3sin^(-1)((2x)/(1+x^2))-4cos^(-1)((1-x^2)/(1+x^2))+2tan^(-1)((2x)/(...

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