" Whe the ceroes of the polynomial five "=x^(2)-p(x+1)-6" then "(alpha+1)(beta+1)=?

If alpha,beta are the zeroes of the polynomial x^(2)-p(x+1)-q , then (alpha+1)(beta+1)=

If alpha,beta are the zeroes of polynomial f(x)=x^2-p(x+1)-c ,then (alpha+1)(beta+1) =

If alpha, beta are the zeros of polynomial f(x) = x^(2) - p(x+1)-c then (alpha + 1) (beta +1 ) = …………

If alpha,beta are the zeros of the polynomial f(x)=x^(2)-p(x+1)-c such that (alpha+1)(beta+1)=0, then c=( a )1(b)0(c)-1(d)2

If alpha, beta are the zeros of the polynomial x^(2) + 6x+2" then " (1/alpha+1/beta)=?

If alpha, beta are the zeroes of the polynomial f(x)= x^2+x+1 , then (alpha+1)(beta+1) =

If alpha,beta are the zeros of the polynomial p(x)=x^(2)-a(x+1)-b such that (alpha+1)(beta+1)=0 then find value of b

If alpha and beta are the zeroes of the polynomial x^(2)+x+1, then (1)/(alpha)+(1)/(beta) =

If alpha,\ beta are the zeros of the polynomial f(x)=x^2-p(x+1)-c such that (alpha+1)(beta+1)=0 , then c= (a) 1 (b) 0 (c) -1 (d) 2

If alpha,beta are the zeros of polynomial f(x)=x^(2)-p(x+1)-c, then (alpha+1)(beta+1)=(a)c-1(b)1-c(c)c(d)1+c