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If (tan^(-1)x)^(2)+(cot^(-1)x)^(2)=(5 pi...

If `(tan^(-1)x)^(2)+(cot^(-1)x)^(2)=(5 pi^(2))/(8)`, then the value of x is

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The given equation can be written as :
`(tan^(−1)x+cot^(−1)x)^2−2tan^(−1)x(π/2​−tan^(−1)x)=(5π^2)/8​`
`2(tan^(−1)x)^2−2(π/2​)tan^(−1)(x)−(3π^2)/8​=0`
`tan^(−1)x=−π/4​` or `(3π)/4`​
Hence, `tan^(−1)x=1`
...
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