6*(m-1)/(m-2)=1-(m-2)/(3)

m-(m-1)/2=1-(m-2)/3

(m-1)/(m-4)=(2m-3)/(3m-8)

Solve each of the following equation. Also, verify the result in each case. (6x-2)/9+(3x+5)/(18)=1/3 2. m-(m-1)/2=1-(m-2)/3

If l : m = 2 (1)/(2) : 1(2)/(3) and m : n = 1 (1)/(4) : 3 (1)/(2) , find l : m : n

Simplify : (2^n.6^(m+1).10^(m-n).15^(m+n-2))/(4^m.3^(m+n).25^(m-1)) .

Show that the distance between (1,-1) and ((2m^2)/(1+m^2),(1-m)^2/(1+m^2)) is not depend on m

In triangle ABC m_(1),m_(2),m_(3) are the lenghts of the medians through A,B and C respectively . If C=(pi)/(2) , then (m_(1)^(2)+m_(2)^(2))/(m_(3)^(2)) =

Find the value of m m - ( ( m -1 ) /2) = 1 - ( ( m - 2 ) /3)

m(m-1)(m-2)...3.2.1=