If `alpha=tan^(-1)(t a n(5pi)/4)a n dbeta=tan^(-1)(-tan(2pi)/3),t h e n` `4alpha=3beta` (b) `3alpha=4beta` (c) `alpha-beta=74alpha=(3beta)/(12)` none of these

Explanation

To solve the problem, we need to find the relationship between the angles \( \alpha \) and \( \beta \) defined as follows:

\[ \alpha = \tan^{-1}(\tan(5\pi/4)) \]
\[ \beta = \tan^{-1}(-\tan(2\pi/3)) \]
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