If `y=tanx+secx ,p rov et h a t(d^2y)/(dx^2)=(cosx)/((1-sinx)^2)`

Explanation

To prove that \( \frac{d^2y}{dx^2} = \frac{\cos x}{(1 - \sin x)^2} \) for the function \( y = \tan x + \sec x \), we will follow these steps:

### Step 1: Differentiate \( y \) to find \( \frac{dy}{dx} \)

Given:
\[ y = \tan x + \sec x \]
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