Ce is the first element of lanthanide se...

Ce is the first element of lanthanide series.
What is the most suitable E.C. of `Ce^(3+)` ?

`[Xe]4f^(1) 5d^(1) 6s^(2)`

`[Xe] 4f^(2)`

`[Xe] 4f^(1)`

`[Xe]4f^(0)`

Verified by Experts

The correct Answer is:

`Co: [Xe]4f^(1)5d^(1)6s^(2)`

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Last element of lanthanide series is:

Lawerncium

Lutetium

Thulium

Hafnium

Only unfilled 3d-orbitals

unfilled 3d and 4d-orbitals

unfilled 4d and 4f-orbitals

unfilled 4f and 5d-orbitals

only 6s-orbital is filled

4d and 4f-orbitals are unfilled

3d and 5d-orbitals are unfilled

4f-and 5d-orbitals are filled