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If y=(a x+b)/(x^2+c), then (2x y1+y) y3=...

If `y=(a x+b)/(x^2+c), then (2x y_1+y) y_3=`

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Given
`y=(a x+b)/(x^2+c)`
=`(x^2+c)y=(ax+b)`
differentiating both side we get
=`(x^2+c)y_1 +2xy=(a)`
or,`y_1=(a-2xy)/(x^2+c)`
again differentiating both side we get
...
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