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If y=(log)e(x/a)^x ,then x^3y2=...

If `y=(log)_e(x/a)^x` ,then `x^3y_2=`

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`y=(log)_e(x/a)^x`
`y=x(log)_e(x/a)`
`y_1=ln(x/a)+x(1/x)`
`y_1=ln(x/a)+1--(i)`
`y_2=1/x---(ii)`
So,
`x^3y_2`
...
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