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If sin^(-1) (1 – x) – 2sin^(-1) x = π / ...

If `sin^(-1) (1 – x) – 2sin^(-1) x = π / 2`,then x is equal to

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`sin^(-1) (1 – x) – 2sin^(-1) x = π / 2`
`sin^(-1) (1 – x) = π / 2 + 2 sin^(-1) (x)`
`(1 – x) = sin (π / 2 + 2 sin^(-1) x) `
`(1 – x) = cos (2 sin^(-1) x)`
...
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