For the system of equitions: `x+2y+3z=1` `2x+y+3z=2` `5x+5y+9z=4` there is only one solutions there exists infinitely many solution there is no solution (d) none of these

Explanation

Given system of equitions:

`x+2y+3z=1`


`2x+y+3z=2`


`5x+5y+9z=4`
we have,


determinant,
`abs(A)= |(1,2,3),(2,1,3),(5,5,9)|`
`∣A∣=1(9−15)−2(18−15)+3(10−5)`
`∣A∣=−6−6+15`

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