Let `Delta_t=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|and Delta_2=|(alpha_1,beta_1,gamma_1),(alpha_2,beta_2,gamma_2),(alpha_3,beta_3,gamma_3)|,` then `Delta_1 xx Delta_2` can be expressed as the sum of how many determinants ?

If Delta=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)| and Delta_1=|(a_1+pb_1,b_1+qc_1,c_1+ra_1),(a_2+pb_2,b_2+qc^2,c^2+ra^2),(a_3+pb_3,b_3+qc_3,c_3+ra_3)| then Delta_1=

If Delta=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)| and Delta_1=|(a_1+pb_1,b_1+qc_1,c_1+ra_1),(a_2+pb_2,b_2+qc^2,c^2+ra^2),(a_3+pb_3,b_3+qc_3,c_3+ra_3)| then Delta_1=

If Delta=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)| and Delta_1=|(a_1+pb_1,b_1+qc_1,c_1+ra_1),(a_2+pb_2,b_2+qc_2,c _2+ra_2),(a_3+pb_3,b_3+qc_3,c_3+ra_3)| then Delta_1=

If Delta=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)| and Delta_1=|(a_1+pb_1,b_1+qc_1,c_1+ra_1),(a_2+pb_2,b_2+qc^2,c^2+ra^2),(a_3+pb_3,b_3+qc_3,c_3+ra_3)| then Delta_1=

Consider Delta=|(alpha,beta,gamma),(alpha^2,beta^2,gamma^2),(beta+gamma,gamma+alpha,alpha+beta)| Apply R_3rarrR_1+R_3

Delta=|{:(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3):}|and Delta'|{:(A_1,B_1,C_1),(A_2,B_2,C_2),(A_3,B_3,C_3):}| where A_1,B_1,C_1,A_2,B_2,……… are respectively the cofactors of the elements a_1,b_1,c_1,a_2,b_2,….. of the determinant then Delta'=........

If Delta=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|, then the value of Delta_1=|(a_1+2b_1+3c_1,2c_1+3c_1,c_1),(a_2+2b_2+3c_2,2b_2+3c_2,c_2),(a_3+2b_3+ 3c_3,2b_3+3c_3,c_3)| is equal to

Prove that |[[alpha,beta,gamma],[alpha^2,beta^2,gamma^2],[alpha^3,beta^3,gamma^3]]|= alpha beta gamma (alpha-beta)(beta-gamma)(gamma-alpha)

A : If (2,1,-3) , (-2,3,4) , (1,2,2) are the midpoints of bar(BC) ,bar( CA), bar(AB) of DeltaABC then A=(-3,4,9) R : If (alpha_1,beta_1,gamma_1), (alpha_2,beta_2,gamma_2),(alpha_3,beta_3,gamma_3) are the midpoints of the sides bar(BC),bar(CA),bar(AB) of DeltaABC then A=(alpha_2+alpha_3-alpha_1,beta_2+beta_3-beta_1,gamma_2+gamma_3-gamma_1)