The points on the curve `9y^2=x^3`, where the normal to the curve makes equal intercepts with the axes are
(A) `(4,+-8/3)`
(B) `(4,(8)/3)`
(C) `(4,+-3/8)`
(D) `(+-4,3/8)`

Explanation

To find the points on the curve \( 9y^2 = x^3 \) where the normal to the curve makes equal intercepts with the axes, we can follow these steps:

### Step 1: Differentiate the curve
The given curve is:
\[ 9y^2 = x^3 \]
To find the slope of the tangent line, we differentiate both sides with respect to \( x \):
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