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The set representing the correct order o...

The set representing the correct order of ionic radius is : a)`Na^(+) gt Mg^(2+) gt Al^(3+) gt Be^(2+) gt Li^(+)` b)`Na^(+) gt Li^(+) gt Mg^(2+) gt Al^(3+) gt Be^(2+)` c)`Na^(+) gt Mg^(2+) gt Al^(3+) gt Li^(+) gt Be^(2+)` d)`Na^(+) gt Mg^(2+) gt Li^(+) gt Be^(2+) gt Al^(3+)`

A

`Na^(+) gt Mg^(2+) gt Al^(3+) gt Be^(2+) gt Li^(+)`

B

`Na^(+) gt Li^(+) gt Mg^(2+) gt Al^(3+) gt Be^(2+)`

C

`Na^(+) gt Mg^(2+) gt Al^(3+) gt Li^(+) gt Be^(2+)`

D

`Na^(+) gt Mg^(2+) gt Li^(+) gt Be^(2+) gt Al^(3+)`

Text Solution

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The correct Answer is:
C
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Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order : SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When conc. H_(2)SO_(4) is electrolysed with high current using Pt electrodes, the product obtained at anode is :

Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order : SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) A mixture containing chlorides of sodium, calcium and zinc is electrolysed in presence f wate. The product obtained at cathode will be :

Electrolysis is an important technique for extraction of metals, and each ion of the solution needs a minimum voltage to get discharged and this value is expressed in terms of discharge potential. For some metal ions the discharge potentials follow the order given below : Li^(+) gt K^(+) gt Ca^(2+) gt Na^(+) gt Mg^(2+) gt Al^(3+) gt Zn^(2+) gt Fe^(2+) gt Ni^(2+) gt H_(3)O^(+) gt Cu^(2+) gt Hg_(2)^(2+) gt Ag^(+) gt Au^(3+) For some anions the discharge potentials are in the order : SO_(4)^(2-) gt NO_(3)^(-) gt OH^(-) gt Br^(-) gt I^(-) When aqueous solution of cupric bromide is electrolyzed the product obtained at cathode will be :

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