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S : ""^(14)C is beta-emiter. E : Its ...

S : `""^(14)C` is `beta`-emiter.
E : Its electrons are loosely bonded in comparison to `""^(12)C` and `""^(13)C`

A

Both S and E are correct and E is cporrect explaination of S

B

Both S and E are correct and E not correct explaination of S

C

S is correct but E is wrong

D

S is wrong but the E is correct

Text Solution

Verified by Experts

The correct Answer is:
c
`N//A`
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Carbon 14 is used to determine the age of organic material. The procerdure is based on the formation of .^(14)C by neutron capture in the upper atmosphere. ._(7)^(14)N + ._(0)^(1)n rarr ._(6)^(14)C + ._(1)n^(1) .^(14)C is abosorbed by living organisms during phostosythesis. The .^(14)C content is constant in living organisms once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of .^(14)C in the dead being, falls due to the decay which .^(14)C undergoes. ._(6)^(14)C rarr ._(7)^(14)C + beta^(-) The half-life period of .^(14)C is 5770 years. The decay constant (lambda) can be calculated by using the following formula lambda = (0.693)/(t_(1//2)) The comparison fo the beta^(-) activity fo the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation the materail form the living cycle. The method however, ceases to be accurate ever periods longer than 30,000 years. The proportaion of .^(14)C to .^(12)C living matter is 1:10^(12) . A nulcear explosion has taken place leading to increases in conventration of ^(14)C in nearly areas. ^(14)C concentration is C_(1) in nearby areas and C_(2) in areas far away. If the age of the fossil is detemined to be T_(1) and T_(2) at the places respectively, then:

A radioactive material emits 20 beta - perticles per sec . At 10^(@)C . It the temperature is increased to 20^(@)C at 10^(@)C . It the temperature is increased to 20^(@)C then the emission rate of beta- particles per sec is

Carbon 14 is used to determine the age of organic material. The procerdure is based on the formation of .^(14)C by neutron capture in the upper atmosphere. ._(7)^(14)N + ._(0)^(1)n rarr ._(6)^(14)C + ._(1)n^(1) .^(14)C is abosorbed by living organisms during phostosythesis. The .^(14)C content is constant in living organisms once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of .^(14)C in the dead being, falls due to the decay which .^(14)C undergoes. ._(6)^(14)C rarr ._(7)^(14)C + beta^(-) The half-life period of .^(14)C is 5770 years. The decay constant (lambda) can be calculated by using the following formula lambda = (0.693)/(t_(1//2)) The comparison fo the beta^(-) activity fo the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation the materail form the living cycle. The method however, ceases to be accurate ever periods longer than 30,000 years. The proportaion of .^(14)C to .^(12)C living matter is 1:10^(12) . What should be the age of fossil for meainingful determination of its age?