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One mole of a present in a closed vessel...

One mole of a present in a closed vessel undergoes decay as `""_(z)""^(m)Ato""_(Z-4)""^(m-8)B+2""_(2)""^(4)He`. The volume of He collected at NTP a fter 20 days is (`t""_(1//2)=10`days)

A

11.2 litre

B

22.4 litre

C

33.6 litre

D

67.2 litre

Text Solution

Verified by Experts

The correct Answer is:
c
Amount of (A)left=`N""_(0)/2""^(2)(t""_(1//2)xxn=T)`
Amount of (A) decayed=`N""_(0)-N""_(0)/2=(3N(0))/4`
`therefore` Mole of He formed=`2xx3/4N""_(0)`
`=3/2N""_(0)=3/2`mole(`because` 1 mole of (A) is taken)
`therefore` volume of He =`3/2xx22.40=33.6` litre
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