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A radioactivity sample had an initial ac...

A radioactivity sample had an initial activity of 56dpm. After 69.3 minutes, it was found to have an activity of 28dpm, the number of atoms in a sampple having an activity of 10dpm, is `10""^(x)`. The value of x is

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The correct Answer is:
3
`(dN)/(dt)=lamdaNrArr10=0.693/69.3xxN`
N=10""^(3)`
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