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The half of ""(92)""^(238)U against alph...

The half of `""_(92)""^(238)U` against `alpha`-decay is `4.5xx10""^(9)`year. The time taken in year for the decay of `15/16` part of the isotope is

A

`9.0xx10""^(9)`

B

`1.8xx10""^(10)`

C

`4.5xx10""^(9)`

D

`2.7xx10""^(10)`

Text Solution

Verified by Experts

The correct Answer is:
b
`N=N""_(0)/2""^(n)(n=t//t""_(1//2))`
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