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Uranium .(92)U^(238) decayed to .(82)Pb^...

Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))`
`t_(1//2)` of `U^(238) = 4.5 xx 10^(9)` years
Atomic mass of `U^(238)` is 238.125 amu. Its packing fraction will be

A

6.25

B

0.125

C

12.5

D

5.25

Text Solution

Verified by Experts

The correct Answer is:
d
`t=(2.303xxt""_(1//2))/0.693log.(1+(pb""^(206))/U""^(238))`
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