A small amount of solution containing a radioactive nucleide `A""^(x)` was administrated into the blood of a patient. The activity of the nucliede id `2xx10""^(3)`dps. Its half life is 15 hours. After 5 hours a sample of the blood drawn out from the patient. It,s activity was 16 dpm per mL.
What is the volume of the 'blood' in the patient? (Log(1.26)=0.1)

Options

A. 2.92 lit
B. 3.95 lit
C. 4.92 lit
D. 5.95 lit

Answer

d

Explanation

Initial activity =`2xx10""^(3)`dps after 5 hours the activity is=x
`therefore``0.693/15=2.303/5log.(2xx10""^(3))/x,thereforex=1.588xx10""^(3)dps`
So `1.588xx10""^(3)xx60=16V V=5.95l`lit