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In electrolysis of NaCl when Pt electrod...

In electrolysis of `NaCl` when `Pt` electrode is taken `H_(2)` is liberated at cathode while `Hg` cathode it forms sodium amalgam because

A

Hg is more inert than Pt

B

More voltage is required to reduce `H^(+)` at Hg than at Pt

C

Na is dissolved in Hg while it does not dissolve in Pt

D

Conc. Of `H^(+)` ions is larger when Pt electrode is taken

Text Solution

Verified by Experts

The correct Answer is:
B
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NARAYNA- ELECTRO CHEMISTRY-C.U.Q
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  2. In an electrolytic cell, the flow of electrons is form

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  3. In electrolysis of NaCl when Pt electrode is taken H(2) is liberated a...

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  4. Faraday's laws of electrolysis are related to the

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  5. The unit of electrochemical equivalent is

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  10. The number of faradays required to liberate 1 mole of any element indi...

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  11. 6.24xx10^(19) electrons are equal approximately to

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  12. The metal which cannot liberate H(2) gas from hydrochloric acid

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  18. For the feasibility of a redox reaction in a cell, the emf should be.

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