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The molar conductance of acetic acid at ...

The molar conductance of acetic acid at infinite dilution is `lambda_(oo)`. If the conductivity of `0.1M` acetic acid is S, the apparent degree of ionisation is

A

`(10000S)/(lambda_(oo))`

B

`(10S)/(lambda_(oo)`

C

`(lambda_(oo))/(100S)`

D

`(100000)/(lambda_(oo)S)`

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=(lambda_(v))/(lambda_(oo))`, we know that `lambda_(v)=(Kxx1000)/(M)`
`therefore alpha=((10^(4))xx(S))/(lambda_(oo))`
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