Consider the following four electrodes:
`A=Cu^(2+)(0.0001M)//Cu_((s))`
`B=Cu^(2+)(0.1M)//Cu_((s))`
`C= Cu^(2+)(0.01M)//Cu_((s))`
`D=Cu^(2+)(0.001M)//Cu_((s))`
If the standard reduction potential of `Cu^(+2)//Cu` is `+0.34V`, the reduction potentials (in volts) of the above electrodes follow the order

Options

A. `AgtDgtCgtB`
B. `BgtCgtDgtA`
C. `CgtDgtBgtA`
D. `AgtBgtCgtD`

Answer

B

Explanation

For Metal electrode
`E=E^(@)+(0.059)/(n)log[Cu^(+2)]`