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An electric current is passed through a copper voltmeter and a water voltameter connected in series. If the copper voltameter now weights 16 mg less, hydrogen liberated at the cathode of the water voltmeter measures at STP about

A

`4.0`ml

B

`5.6`ml

C

`6.4`ml

D

`8.4`ml

Text Solution

Verified by Experts

The correct Answer is:
B
`(W_(1))/(W_(2))=(E_(1))/(E_(2))`
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