`0.2` faraday charge is passed in 1 litre solution containing `0.1` molar `Fe^(+3)` ions. How many moles of iron get deposited at cathode assuming only iron is reduced in electrolytic process.
`(E_(Fe^(+3)//Fe^(+2))^(0)=0.77"V E"_(Fe^(+2)//Fe)^(0)=-0.44V)`

Options

A. `0.05` moles
B. `0.033` moles
C. `0.67` moles
D. `0.1` moles

Answer

A

Explanation

`E_(Fe^(+3)//Fe)^(0)=-0.037V` as the reduction potential of `Fe^(3+)//Fe^(+2)` is higher inititaly all `FE^(+3)` converts into `Fe^(+2)`, which further gets reduced to metallic iron.