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The specific conductance at 289 K of AgC...

The specific conductance at 289 K of AgCl is `1.826xx10^(-6)ohm^(-1)cm^(-1)`. The ionic conductance of `Ag^(+)` and `Cl^(-)` are `61.92` and `61.92` and `76.36` respectively. What is the solubility of AgCl in water?

A

`1.1xx10^(-2)g^(-1)`

B

`1.9xx10^(-3)gL^(-1)`

C

`1.3xx10^(5)gL^(-1)`

D

`2.1xx10^(-6)gL^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Solubility `(S)=(Kxx1000)/(mu)`
`mu=61.92+76.34=138.26`
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