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The emf of given cell Pt - underset(P(1)...

The `emf` of given cell `Pt - underset(P_(1))(H_(2))|H^(+)|underset(P_(2))(H_(2) - Pt` is :

A

`(RT)/(F)log.(P_(1))/(P_(2))`

B

`(RT)/(2F)"log e"(P_(1))/(P_(2))`

C

`(RT)/(F)"log e"(P_(2))/(P_(1))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

`underset(p_(1))(H_(2))rarr2H^(+)+2e`
`2H^(+)+2erarrunderset(p_(2))(H_(2))`
`E_(cell)=E_(OP_(H))^(0)+E_(RP_(H))^(0)+(RT)/(2F)loge([P_(H_(2))]_(1))/([P_(H_(2))]_(2))`
`=(RT)/(2F)loge(P_(1))/(P_(2))`
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