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For a cell reaction involving a two-ele...

For a cell reaction involving a two-electron change, the standard e.m.f. of the cell is found to be `0.295V` at `25^(@)C`. The equilibrium constant of the reaction at `25^(@)C` will be:

A

`1xx10^(-10)`

B

`29.5xx10^(-2)`

C

10

D

`1xx10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(cell)^(0)=(0.059)/(2)logK_(C)`
`0.295=(0.059)/(2)logK_(c)`
`rArrK_(c)=1xx10^(10)`
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