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The limiting molar conductivities Lambda...

The limiting molar conductivities `Lambda^@` for `NaCL, KBr` and `KCI` are ` 126, 152` and `150 S cm^2 ,ol^(-1)` respectively . The `Lambda^@` fro `NaBr S cm^2 "mol"^(-1)` is :

A

302

B

176

C

278

D

128

Text Solution

Verified by Experts

The correct Answer is:
D
`Lambda_(NaBr)^(0)=Lambda_(NaCl)^(0)+Lambda_(KBr)^(0)-Lambda_(CKl)^(0)`
`=126+152-150=128Scm^(2)mol^(-1)`
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