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The cell , Zn | Zn^(2+) (1M) || Cu^(2+) ...

The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :

A

antilog `(24.08)`

B

`37.3`

C

`10^(37.3)`

D

`9.65xx10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(cell)=E_(cell)^(@)-(0.0591)/(n)logQ`
where, `Q=([Zn^(2+)])/([Cu^(2+)])` for complete dicharge
`E_(cell)=0`
So, `E_(cell)^(@)=(0.0591)/(2)log.([Zn^(2+)])/([Cu^(2+)])`
`rArr[([Zn^(2+)])/([Cu^(2+)])]=10^(37.3)`
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