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Oxidising power of chlorine in aqueous s...

Oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below
`(1)/(2)CL_(2)(g)overset((1)/(2)Delta_(diss)H^(Theta))(rarr)Cl(g)overset(DeltaH_(Eg)^(Theta))(rarr)`
`Cl^(-)(g)overset(Delta_(hyd)H^(Theta))(rarr)Cl^(-)(aq)`
The energy involved in the conversion of `(1)/(2)Cl_(2)(g)` to
`Cl^(-)(aq)`
(Using the data `Delta_(diss)H_(Cl_(2))^(Theta)=240KJ mol^(-1)`)
`Delta_(Eg)H_(Cl)^(Theta)=-349KJmol^(-1)` ,
`Delta_(Eg)H_(Cl)^(Theta)=-381KJmol^(-1)`) will be

A

`+"152 kJ mol"^(-1)`

B

`-"610 kJ mol"^(-1)`

C

`-"850 kJ mol"^(-1)`

D

`+"120 kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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oxidising power of chlorine in aqueous solution can be determined by the parameters indicated below: Calculate the energy involved in the conversion of (1)/(2)Cl_(2)(g)"to"Cl^(-)(aq) Using the data , DeltaH_("disso"(Cl_(2)))^(@)=240KJmol^(-1), DeltaH_("eg"(Cl_(2)))^(@)=-349KJmol^(-1), DeltaH_("hydroation"(Cl_(2)))^(@)=-381KJmol^(-1),

Find DeltaH of the process NaOH(s) rarr NaOH(g) Given: Delta_(diss)H^(Theta)of O_(2) = 151 kJ mol^(-1) Delta_(diss)H^(Theta) of H_(2) = 435 kJ mol^(-1) Delta_(diss)H^(Theta) of O-H = 465 kJ mol^(-1) Delta_(diss)H^(Theta) of Na -O = 255 kJ mol^(-1) Delta_(soln)H^(Theta)of NaOH = - 46 kJ mol^(-1) Delta_(f)H^(Theta) of NaOH(s) =- 427 kJ mol^(-1) Delta_("sub")H^(Theta) of Na(s) = 109 kJ mol^(-1)

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