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Which kind of isomerism is exhibited by ...

Which kind of isomerism is exhibited by `[Co(EDTA)]`-

A

Optical & geometrical isomerism

B

Geometrical isomerism

C

Optical isomerism

D

no isomerism

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The correct Answer is:
To determine the type of isomerism exhibited by the complex `[Co(EDTA)]`, we can follow these steps: ### Step 1: Identify the Ligand and Its Denticity EDTA (ethylenediaminetetraacetic acid) is a hexadentate ligand, meaning it can form six bonds with a metal ion. It has two nitrogen atoms and four carboxylate groups that coordinate to the metal. **Hint:** Remember that the denticity of a ligand refers to the number of donor atoms it has that can coordinate to a metal center. ### Step 2: Analyze the Coordination Geometry Cobalt typically exhibits octahedral geometry when coordinated with six donor atoms. In the case of `[Co(EDTA)]`, the six donor atoms from EDTA will occupy the vertices of an octahedron around the cobalt ion. **Hint:** Consider the geometry of the complex formed by the ligand and the metal ion, as it can influence the type of isomerism. ### Step 3: Consider Possible Isomerism Types In coordination complexes, the main types of isomerism include: - Geometrical isomerism (cis/trans) - Optical isomerism (enantiomers) - Linkage isomerism - Coordination isomerism For `[Co(EDTA)]`, geometrical isomerism (cis/trans) is typically observed in complexes where there are different arrangements of ligands around the metal ion. **Hint:** Think about whether the arrangement of the ligands can lead to different spatial configurations. ### Step 4: Evaluate Geometrical Isomerism In the case of `[Co(EDTA)]`, due to the nature of the EDTA ligand and its ability to form chelate rings, there are no distinct cis or trans configurations possible. The complex does not have a plane of symmetry, which means it cannot exhibit geometrical isomerism. **Hint:** Check if the complex can have different arrangements of ligands that lead to distinct geometrical forms. ### Step 5: Determine Optical Isomerism Since `[Co(EDTA)]` does not have a plane of symmetry and cannot exhibit geometrical isomerism, it can exhibit optical isomerism. This means that the complex can exist in two non-superimposable mirror images (enantiomers). **Hint:** Optical isomerism is often indicated by the absence of symmetry elements in the structure. ### Conclusion The complex `[Co(EDTA)]` exhibits optical isomerism due to the lack of a plane of symmetry and the presence of chiral centers in the arrangement of the ligand around the cobalt ion.

To determine the type of isomerism exhibited by the complex `[Co(EDTA)]`, we can follow these steps: ### Step 1: Identify the Ligand and Its Denticity EDTA (ethylenediaminetetraacetic acid) is a hexadentate ligand, meaning it can form six bonds with a metal ion. It has two nitrogen atoms and four carboxylate groups that coordinate to the metal. **Hint:** Remember that the denticity of a ligand refers to the number of donor atoms it has that can coordinate to a metal center. ### Step 2: Analyze the Coordination Geometry ...
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NARAYNA-COORDINATION COMPLEXES-EXERCISE -2
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  5. [Pt(NH(3))(NO(2))Ph(NH(2)OH)]^(+), the no. of geometrical isomers incl...

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  7. Oxidation number of Cr in the following complex is

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  8. [Cr(NH(3))(5)Br]Cl and [Cr(NH(3))(5)Cl]Br can be distinguished by/and ...

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  9. If excess of AgNO(3) solution is added to 100 mL of a 0.024 M solution...

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  11. Which of the following is correct IUPAC name of any compound.

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  12. [Fe^(II)Cl(CN)(4)(O(2))]^(4-) is named as :

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  13. Which of the following complexes has the least molar conductivity in t...

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  14. Hybridization and magnetic moment of [Cu(NH(3))(4)]^(2+) and [Mn(CN)(6...

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  15. Lead poisoinig in the body can be removed by:

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  16. How many geometrical isomers are possible for [Pd^(2+)(NH(2)-CH(CH(3))...

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  18. Find the correct pair for Column-I and Column-II :

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  19. Which of the following complexes exhibit optical isomerism?

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  20. Coordination compounds plays many important roles in animals and plant...

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