Bonding in metal carbonyls is represented by the end structures.
`overset(M-C-=O" "harr" "M=C=O)(I" "II)`
The contribution of I and II to the real structure depends upon the extent of `pi-` back bonding. Both `sigma` donation and `pi-` back bonding are synergitc. The filled orbitals CO overlap with vacant metal d orbitals which is called `sigma` donation. The filled metal d orbitals overlap with `pi` antibondig moleculat orbital of CO. which is called `pi-`back bonding .
Which one of the following has the highest C-O bond length?

Options

A. `[Cr(CO)_(6)]`
B. `[Ti(CO)_(6)]^(2-)`
C. `[Mn(CO)_(5)]^(+)`
D. `[Fe(CO)_(5)]`

Answer

b

Explanation

More negative charge on Ti atom , which pumps more electrons into `pi^(**)` MO of CO , So bond order decreases , bond length increases.