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1.245g of CuSO(4).xH(2)O was dissolved i...

`1.245g` of `CuSO_(4).xH_(2)O` was dissolved in water and `H_(2)S` was passed until CuS was completely precipitated. The `H_(2)SO_(4)` Produced in the filtrated required 10 ml of 1N NaOH solution . X cannot be

A

3

B

10

C

5

D

6

Text Solution

Verified by Experts

The correct Answer is:
A,B,D
meq's `CuSO_(4).xH_(2)O=`meq's `NaOH=10`
`:. `Geq's `CuSO_(4).xH_(2)O=10xx10^(-3)=1.245g`
`:. 1` Geq's `=124.5g`
Eq. Mass of `CuSO_(4).xH_(2)O=(63.5+32+64+18x)/(2)=124.5,x=5`
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