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When phosphate radical with ammonium mol...

When phosphate radical with ammonium molybdate, the colour of precipitate obtained as

A

Green

B

Yellow

C

White

D

Brown

Text Solution

Verified by Experts

The correct Answer is:
2
`Ba_(3)(PO_(4))_(2)+6HNO_(3)rarr 3Ba(NO_(3))_(2)+2H_(3)PO_(4)`
`underset(("Ammonium phosphomolybdate")("yellow"))((NO_(4))_(3)PO_(4).12MoO_(3)+12H_(2)O)+21NH_(4)NO_(3)`
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Explore conceptually related problems

A yellow precipitate is obtained when:

A red colouration or precipitate is not obtained when:

An organic compound 'A' is oxidized with Na_(2)O_(2) followed by boiling with HNO_(3) . The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on above observation,the element present in the given compound is :

Ammonium molybdate test is used for the estimation of:

Ammonium molybdate test is used for the estimation of:

Knowledge Check

  • A yellow precipitate is obtained when:

    A
    lead acetate solution is treated with `K_(2)CrO_(4)`
    B
    `Pb(NO_(3))_(2)` solutino is treated with `K_(2)CrO_(4)`
    C
    `AgNO_(3)` solution treated with KI
    D
    `H_(2)S` is passed thorugh a solution of `CdSO_(4)`

  • A white precipitate is obtained when:

    A
    a solution of `BaCl_(2)` is treated with `Na_(2)SO_(3)`
    B
    a solution of `NaAlO_(2)` is heated with `NH_(4)Cl`
    C
    `H_(2)S` is pased through a solution of `ZnSO_(4)`
    D
    a solution of `ZnSO_(4)` is treated with `Na_(2)CO_(3)`

  • A red colouration or precipitate is not obtained when:

    A
    `Fe^(3+)` reacts with potassium thiocyanate
    B
    `Fe^(2+)` reacts with dimethylglyoxime.
    C
    `Hg^(2+)` reacts with potassium iodide.
    D
    None
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