Home
Class 12
CHEMISTRY
Cu^(2+) and Cd^(2+) are separated by fir...

`Cu^(2+)` and `Cd^(2+)` are separated by first adding KCN solution and then passing `H_(2)S` gas.
KCN reduces `Cu^(2+)` to `Cu^(+)` and forms a complex with it.

Text Solution

Verified by Experts

The correct Answer is:
1
Benzaldehyde has no reaction with Fehling's solution
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS

    NARAYNA|Exercise LEVEL -III|32 Videos

  • QUALITATIVE ANALYSIS

    NARAYNA|Exercise LEVEL-IV (NCERT)|2 Videos

  • QUALITATIVE ANALYSIS

    NARAYNA|Exercise LEVEL -II (C.W.)|41 Videos

  • PRACTICAL ORGANIC CHEMISTRY

    NARAYNA|Exercise SUBJECTIVE_TYPE|1 Videos

  • SOLID STATES

    NARAYNA|Exercise EXERCISE-4|18 Videos

Similar Questions

Explore conceptually related problems

Statement-1 : Cu^(2+) and Cd^(2+) ions form complexes with excess of potassium cyanide solution. Statement-2 : On passing H_(2)S gas, complex [Cu(CN)_(4)]^(3-) is not effected but [Cd(CN)_(4)]^(2-) gives yellow precipitated.

Coordination compounds plays many important roles in animals and plants. The are essential in the storage and transport of oxygen as electrons transfer agents as catalysts and in photosynthesis Wide range of application in daily life takes place through formation of complexes Photographic fixing qualitative and quantitative analysis purification of water metallurgical extraction are some specific worth mentioning Cu^(2+) and Cd^(2+) both are precipitated as sulphides on passing H_(2)S gas in dil HCI medium However, precipitation of Cu^(2+) is prevented by (a) Adding excess of K_(4)[Fe(CN)_(6)] when Cd^(2+) is only precipitated (b) Adding excess of KNC when Cu^(2+) for stable complex [Cu(CN)_(4)]^(3-) and Cd^(2+) forms unstable complex [Cd(CN)_(4)]^(2-) (c ) All of the above

In a solution containing Cu^(2+) and Cd^(2+) dil. H_(2)SO_(4) is added followed by iron filings. The solution is warmed and NH_(4)OH is added to reduce the acidity followed by passing of H_(2)S gas. The ppt. obtained will be

A: Copper rod turns colourless solution of zinc sulphate to blue. R: Zinc reduce Cu^(2+) " ions to " Cu^(+)

During the qualitative analysis of a mixture containing Cu^(2+) and Zn^(2+) ions, H_(2)S gas is passed through and acidified solution containing these ions in order to test Cu^(2+) alone. Explain briefly.