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If `a , b , c` are distinct real numbers and the system of equations `a x+a^2y+(a^3+1)z=0` `b x+b^2y+(b^3+1)z=0` `c x+c^2y+(c^3+1)=0` has a non-trivial solution, show that `a b c=-1`

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To solve the problem, we need to show that if the system of equations has a non-trivial solution, then \(abc = -1\). We will use the concept of determinants to find the condition for non-trivial solutions. ### Step-by-Step Solution: 1. **Write the system of equations in matrix form**: The given equations can be represented in the form of a matrix: \[ \begin{bmatrix} ...
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