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If the system of equations `x=c y+b z` `y=a z+c x` `z=b x+a y` has a non-trivial solution, show that `a^2+b^2+c^2+2a b c=1`

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Equation will have no trivial solution when
`|[​−1,c,b],[​c,−1,a],[​b,a,−1]|=0`
=`(−1)(1−a^2)−c(−c−ab)+b(ac+b)=0`
=`a^2+b^2+c^2+2abc=1`
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